Logstash version: 6.5.0
How do we convert epoch millisecond to datetime? Thanks in advance.
Below parses data and in Kibana is seen as below which is wrong.
(t) epoch_time: 1542765548000000000
Input log content as below 
value=9663.8 1542765548000000000
value=9736.7 1542765548000000000
value=10453.89 1542765548000000000
logstash config file 
filter {
    grok {
        match => { "message" => "value=%{BASE10NUM:cpu_value}\ %{PROG:epoch_time}"}
    }
    date {
        match => [ "epoch_time","UNIX_MS" ]
        target => "myTime"
    }
} 
            
              
            
           
          
            
            
              That looks like nanoseconds and not milliseconds. Drop the last 6 digits and I think you should get the expected timestamp with that date filter.
             
            
              
            
           
          
            
              
                sumitbiswas  
              
                  
                    November 21, 2018, 12:04pm
                   
                  3 
               
             
            
              Hi Christian,
Thanks for the suggestion. Can you please suggest how do we remove last 6 digits?
             
            
              
            
           
          
            
              
                Eniqmatic  
              
                  
                    November 21, 2018, 12:20pm
                   
                  4 
               
             
            
              The obvious way would be to divide by 1000000.
You could do this using a ruby filter first:
ruby {
                            code => "event.set('epoch_time_convert', event.get('epoch_time') / 1000000)"
}
Which will give you a field epoch_time_convert: 1542765548000
Then do:
date {
    match => [ "epoch_time_convert","UNIX_MS" ]
    target => "myTime"
} 
            
              1 Like 
            
            
           
          
            
            
              The easiest way would probably be to change your grok pattern to capture the last 6 digits separately.
             
            
              
            
           
          
            
            
              Thanks Eniqmatic and Christian for your suggestions. It solved the problem.
             
            
              
            
           
          
            
              
                system  
              
                  
                    December 19, 2018,  1:24pm
                   
                  7 
               
             
            
              This topic was automatically closed 28 days after the last reply. New replies are no longer allowed.