Ruby filter usage to divide value and create new events


(PaVliK) #1

Hello,

I have the following event:

             "message" => "2017-01-02 08:00;2017-01-02 09:00;30;Item1, Item2, Item3",
            "@version" => "1",
          "@timestamp" => "2017-01-02T08:00:00.000Z",
                "host" => "xxx",
                "type" => "aaa",
               "stopt" => "2017-01-02 09:00",
                "time" => 24,
               "items" => "Item1, Item2, Item3",

and based on that I would like to:
1.Create new, separate event for every item on items list
2.Divide the time value by the total number of items (e.g. we have 24 and 3 items total - so every new event should have "time" => 8)
3.Delete the original event

so the first new event should look like below:

"message" => "2017-01-02 08:00;2017-01-02 09:00;30;Item1",
            "@version" => "1",
          "@timestamp" => "2017-01-02T08:00:00.000Z",
                "host" => "xxx",
                "type" => "aaa",
               "stopt" => "2017-01-02 09:00",
                "time" => 8,
               "items" => "Item1",
                "tags" => [

I'm not able to achive this using the built-in Logstash filters so ruby() is the only solution. Can you help me with that?

Thanks in advance
PaVliK


(Magnus B├Ąck) #2

You can use the mutate filter's split option to turn the items string into an array. After that the following ruby filter (for Logstash 2.4+) should take care of the division:

ruby {
  code => "event.set('time', event.get('time') / event.get('items').length) unless event.get('time').nil?"
}

Finally, use the clone filter on the items field to split the original event in multiple copies.


(system) #3

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