query_string case:
((a|b)+(c|d))~10 ==> ((a+c)~10)|((a+d)~10)|((b+c)~10)|((b+d)~10)
Can this be true,What should I do if I want to do this.
Can you clarify what you mean here, it's not clear what this has to do with a query_string query.
"query": " +(+(keys:"a" keys:"b") +(keys:"c" keys:"d"))~10", Word spacing does not take effect。
I want C or D to appear at the same time as a, so that the word spacing of a and C is 10, or the word spacing of a and D is 10. query_string How to achieve this.
Hi. Span or interval queries support this but require JSON syntax.
(a|b|c|d|e|f|g|h|i|j)+(A|B|C|D|E|F|G|H|I|J)+(Aa|Bb|Cc|Dc|Ee|Ff|Gg|Hh|Ii|Jj)
Combination number is 1000,Using span or interval, the generated statement is too long and the execution consumes too much CPU
I hope this part of the work is implemented by the query parser
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