Qerying only those documents, which has their value of some field never contained by another documents' field


(Daulet) #1

Hi dear friends. Is it possible to get documents in such way, where in result we dont have documents which has their value contained by another documents' field..
Let's consider we have following documents:

              "field1": "a"
       },
       "doc2":{
              "field1": "ab"
       },
       "doc3":{
              "field1": "abc"
       },
       "doc4":{
              "field1": "qwerty"
       }
``
So the result will be  **doc3** and **doc4**, because **doc3** contains **doc2** and **doc1**
Thanks in advance!

(Mark Walkom) #2

As I mentioned in your other thread, you cannot do this.


(system) #3

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