Scripting field in Kibana and use it in loop

Elastic Stack Kibana
1

can anyone help me over the scripting field. I am getting an error on running this

def x = doc['index_total'].value;
def y = doc['index_time_in_millis'].value;
{
if ( x > 0) {
def z = y / x;
return z
}
else {
def z = 5 * 0;
return z
}
}
if ( z > 0) {
def l = 0;
return l
}
else {
def f = 1;
return f
}
by creating the "indexing_latency" field and using it in the in loop but this is also throwing an error.

A help would be really appreciated

Best Regards
Shrikant

Best Regards
Shrikant

2

@magnusbaeck please guide me

Best Regards
Shrikant

3

@magnusbaeck Please help me I am stuck here

4

Please do not ping people not already active in the thread and also be patient. This forum is manned by volunteers, so there is no SLA. If you have not received any response within a few days it is generally fine to bump the issue.

When I read your issue, it is not clear exactly what you are trying to do. Can you please describe further? What is the loop you want too use it in? What does the error look like?

5

i am sorry @Christian_Dahlqvist
I am facing a issue
i want to create a script and the script is
def x = doc['index_total'].value;
def y = doc['index_time_in_millis'].value;
{
if ( x >; 0) {
def z = y / x;
return z
}
else {
def z = 5 * 0;
return z
}
}
if ( z > 0) {
def l = 0;
return l
}
else {
def f = 1;
return f
}
first i want to extract the value of Z after that i want to apply condition on that value i.e (z)

like if (z>0.3 && z<0.7) {
def l = 3;
retunr l
}
else {
def m = 0;
return m
}

please help me

Best Regards
Shrikant

6

Please format your code sample properly as it is hard to read. It looks like you are trying to do something like this:

def x = doc['index_total'].value;
def y = doc['index_time_in_millis'].value;

if ( x >; 0) {
  def z = y / x;
  return z
} else {
  def z = 5 * 0;
  return z
}

if ( z > 0) {
  def l = 0;
  return l
} else {
  def f = 1;
  return f
}

As you are calling return z the following if-else block will never be reached. If you describe what you expect your script to do it may be easier to help.

7

@Christian_Dahlqvist
Thankyou so much for the response

I want to first find the indexing latency which is (index_total / index_time_in_millis) and define it as Z.
Now I want that if Z is between (0.3 && 0.7) I want the final output (L) to be 1. and if Z is greater than (0.7 && less than 0.3) I want L to be 0.

Thanks & Regards
Shrikant

8

Then remove the return z clauses as they cause the script to terminate.

9

@Christian_Dahlqvist
Still facing the same issue

def x = doc['index_total'].value;
def y = doc['index_time_in_millis'].value;
for ( x > 0) {
def z = y / x;
}
if (z > 0.3);
def t =1;
return t
}
else {
def m = 0;
return m
}

and i also tried this
def x = doc['index_total'].value;
def y = doc['index_time_in_millis'].value;
if ( x > 0) {
def z = y / x
}
else {
def z = 5*0
}
if (z > 0.3) {
def m = 1;
return m
}
else {
def m = 0;
return m
}

Thanks & Regards
Shrikant

10

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