Kibana 6.2.1 Discover URL without using index pattern ID

Elastic Stack Kibana
1

Hi All,

I am trying to construct a deterministic discover URL but index patterns are mapped to UUIDs and the discover URL uses this ID in the URL. Eg:

http://kibana.url.domain:9000/app/kibana#/discover?...&_a=(columns:!(_source),index:SOME_UUID,....

I did notice though, that for index patterns without a '*', I can replace the UUID with the pattern and the URL works, eg:

http://kibana.url.domain:9000/app/kibana#/discover?...&_a=(columns:!(_source),index:SOME_PATTERN_WITHOUT_A_STAR

However, for patterns with a star in them, this throws an invalid URL:

http://kibana.url.domain:9000/app/kibana#/discover?...&_a=(columns:!(_source),index:PATTERN*,....

If I wrap the pattern between single quotes, the URL is valid but it complains that no such pattern ID exists, eg:

http://kibana.url.domain:9000/app/kibana#/discover?...&_a=(columns:!(_source),index:'PATTERN*',....

What is the trick that I am missing?

P.S.: I think one way to work around this is to create an alias in elasticsearch. However, I was wondering if there is a more direct way that involves only Kibana without me having to create an alias.

Cheers,

2

Hi,

great q. I'm afraid, its not really supported at the moment. I found few ref github issues around this. You can subscribe to this and follow through.

Cheers
Rashmi

3

Many thanks for the answer.

4

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